Gujarati
Hindi
7.Gravitation
hard

Four particles each of mass $m$ are placed at the vertices of a square of side $l.$ The potential energy of the system is

A

$ - \frac{{\sqrt 2 G{m^2}}}{l}\left( {2 - \frac{1}{{\sqrt 2 }}} \right)$

B

$ - \frac{{2G{m^2}}}{l}\left( {2 + \frac{1}{{\sqrt 2 }}} \right)$

C

$ - \frac{{\sqrt 2 G{m^2}}}{l}\left( {\sqrt 2  + \frac{1}{{\sqrt 2 }}} \right)$

D

$ - \frac{{2G{m^2}}}{l}\left( {\sqrt 2  - \frac{1}{{\sqrt 2 }}} \right)$

Solution

$PE = \frac{{ – 4G{m^2}}}{l} – \frac{{2G{m^2}}}{{\sqrt 2 l}} =  – \frac{{2G{m^2}}}{l}\left( {\sqrt 2  + \frac{1}{{\sqrt 2 }}} \right)$

Standard 11
Physics

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