Gujarati
Hindi
10-2.Transmission of Heat
medium

Four rods of same material and having the same cross section and length have been joined, as shown. The temperature of junction of four rods will be........ $^oC$

A

$20$

B

$30$

C

$45$

D

$60$

Solution

$\frac{{{\rm{KA}}(90 – \theta )}}{l} = \frac{{{\rm{KA}}(\theta  – 30)}}{l} + \frac{{{\rm{KA}}(\theta  – {\rm{0}})}}{l} + \frac{{{\rm{KA}}(\theta  – 60)}}{l}$

$90-\theta=3 \theta-90^{\circ}$

$\theta=45^{\circ}$ $C$

Standard 11
Physics

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