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14.Waves and Sound
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Four wires of identical length, diameters and of the same material are stretched on a sonometre wire. If the ratio of their tensions is $1 : 4 : 9 : 16$ then the ratio of their fundamental frequencies are
A
$16 : 9 : 4 : 1$
B
$4 : 3 : 2 : 1$
C
$1 : 4 : 2 : 16$
D
$1 : 2 : 3 : 4$
Solution
(d) $n \propto \sqrt T $
==> ${n_1}:{n_2}:{n_3}:{n_4} = \sqrt 1 :\sqrt 4 :\sqrt 9 :\sqrt {16} = 1:2:3:4$
Standard 11
Physics
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