Four wires of identical length, diameters and of same material are stretched on a sonometre wire. If

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14.Waves and Sound

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Four wires of identical length, diameters and of the same material are stretched on a sonometre wire. If the ratio of their tensions is $1 : 4 : 9 : 16$ then the ratio of their fundamental frequencies are

A

$16 : 9 : 4 : 1$

B

$4 : 3 : 2 : 1$

C

$1 : 4 : 2 : 16$

D

$1 : 2 : 3 : 4$

Solution

(d) $n \propto \sqrt T $
==> ${n_1}:{n_2}:{n_3}:{n_4} = \sqrt 1 :\sqrt 4 :\sqrt 9 :\sqrt {16} = 1:2:3:4$

Standard 11

Physics

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