The molecular formula of felspar is
The solubility of anhydrous $AlCl_3$ and hydrous $AlCl_3$ in diethyl ether are $S_1$ and $S_2$ respectively. Then
Assertion : $Al(OH)_3$ is insoluble in $NH_4OH$ but soluble in $NaOH$ .
Reason : $NaOH$ is strong alkali.
$B{X_3} + N{H_3}\xrightarrow{{R.T}}B{X_3}.N{H_3} + Heat\,of\,adduct\,formation\,\left( {\Delta H} \right)$ The numerical value of $\Delta H$ is found to be maximum for
Diborane $(B_2H_6)$ reacts independently with $O_2$ and $H_2O$ to produce, respectively