Heat required to melt 1, gm of ice is 80, cal . A man melts 60, gm of ice by chewing in one minute.

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10-1.Thermometry, Thermal Expansion and Calorimetry

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Heat required to melt $1\, gm$ of ice is $80\, cal$. A man melts $60\, gm$ of ice by chewing in one minute. His power is ........ $W$

A

$4000$

B

$336$

C

$1.33$

D

$0.75$

Solution

Total heat $ \Rightarrow $ $\frac{{60 \times 80\,cal \times 4.2\,J/s}}{{60\,\sec }} = 336\,W$

Standard 11

Physics

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