Highly electropositive metal (s) can not be commercially extracted by carbon reduction process at hi

English

Gujarati

Hindi

General Principles and processes of Isolation of Elements

medium

Highly electropositive metal $(s)$ can not be commercially extracted by carbon reduction process at high temperature because these

metals combine with carbon to form covalent carbide

metals combine with carbon to form ionic carbide

$\Delta G_f$ of highly electropositive metal oxide is having low negative value

metal oxides are not reduced by carbon

Solution

As they are highly electropositive metals, high purity metal is obtained at cathode. They are not extracted through carbon reduction because they aren't reduced. It they are reduced also, They have impurities. The metal combines with carbon to form ionic carbide

Standard 12

Chemistry

Poling process is used when metal contains

easy

$FeC{r_2}{O_4}$ (chromite) is converted to $Cr$ by following steps :

Chromite $\xrightarrow{I}NaCr{O_4}\,\,\xrightarrow{{II}}\,C{r_2}{O_3}\,\xrightarrow{{III}}\,Cr$

Reagents in $I,\,II$ and $III$ step might be

$I-$ Step $-$ $II-$ Step $-$ $III-$ Step

normal

Impure aluminium is purified by

easy

Match List$-I$ with List $- II :$

List$-I$

(Name of ore/mineral)

List$-II$

(Chemical formula)

$(a)$ Calamine $(i)$ $\mathrm{Zns}$

$(b)$ Malachite $(ii)$ $\mathrm{FeCO}_{3}$

$(c)$ Siderite $(iii)$ $\mathrm{ZnCO}_{3}$

$(d)$ Sphalerite $(iv)$ $\mathrm{CuCO}_{3} \cdot \mathrm{Cu}(\mathrm{OH})_{2}$

Choose the most appropriate answer from the options given below :

easy

(JEE MAIN-2021)

During electrolytic reduction of alumina, two auxiliary electrolytes $X$ and $Y$ are added to increase the electrical conductance and lower the temperature of melt in order to making fused mixture very conducting. $X$ and $Y$ are

easy

List$-I$ (Name of ore/mineral)	List$-II$ (Chemical formula)
$(a)$ Calamine	$(i)$ $\mathrm{Zns}$
$(b)$ Malachite	$(ii)$ $\mathrm{FeCO}_{3}$
$(c)$ Siderite	$(iii)$ $\mathrm{ZnCO}_{3}$
$(d)$ Sphalerite	$(iv)$ $\mathrm{CuCO}_{3} \cdot \mathrm{Cu}(\mathrm{OH})_{2}$

Highly electropositive metal $(s)$ can not be commercially extracted by carbon reduction process at high temperature because these

Solution

Similar Questions

Poling process is used when metal contains

$FeC{r_2}{O_4}$ (chromite) is converted to $Cr$ by following steps : Chromite $\xrightarrow{I}NaCr{O_4}\,\,\xrightarrow{{II}}\,C{r_2}{O_3}\,\xrightarrow{{III}}\,Cr$ Reagents in $I,\,II$ and $III$ step might be $I-$ Step $-$ $II-$ Step $-$ $III-$ Step

Impure aluminium is purified by

During electrolytic reduction of alumina, two auxiliary electrolytes $X$ and $Y$ are added to increase the electrical conductance and lower the temperature of melt in order to making fused mixture very conducting. $X$ and $Y$ are

Start a Free Trial Now

$FeC{r_2}{O_4}$ (chromite) is converted to $Cr$ by following steps :

Chromite $\xrightarrow{I}NaCr{O_4}\,\,\xrightarrow{{II}}\,C{r_2}{O_3}\,\xrightarrow{{III}}\,Cr$

Reagents in $I,\,II$ and $III$ step might be

$I-$ Step $-$ $II-$ Step $-$ $III-$ Step