How will the equations of motion for an object moving with a uniform velocity change ?

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When the object is moving with a uniform velocity, then $v =\mu $ and $a = 0$. In this situation, equation for distance would be as follows :

$s = ut$ and $v^{2}-\mu^{2}=0$

Similar Questions

The following table show os the positon of three persons between $8.00\, am$ to $8.20\, am$.

Time Position (in $km$)  
Person $A$ Person $B$ Person $C$
$8.00 \,am$ $0$ $0$ $0$
$8.05 \,am$ $4$ $5$ $10$
$8.10\, am$ $13$ $10$ $19$
$8.15 \,am$ $20$ $15$ $24$
$8.20\, am$ $25$ $20$ $27$

 $(i)$ Who is moving with constant speed ?

$(ii)$ Who has travelled maximum distance between $8.00\, am$ to $8.05\, am$ ?

$(iii)$ Calculate the average speed of person $'A^{\prime}$ in $k m h^{-1}$

Velocity$-$time graph for the motion of an object in a straight path is a straight line parallel to the time axis.

$(a)$ Identify the nature of motion of the body.

$(b)$ Find the acceleration of the body.

$(c)$ Draw the shape of distance-time graph for this type of motion.

Distinguish between terms speed and velocity.

A body is moving along a circular path of radius $R$. Find the displacement of the body when it completes half a revolution.

A frog hops along a straight line path from point $'A^{\prime}$ to point ${ }^{\prime} B ^{\prime}$ in $10\, s$ and then turns and hops to point ${ }^{\prime} C^{\prime}$ in another $5\, s$. Calculate the average speed and average velocity of the frog for the motion between $(a)(A)$ to $(B)(b)(A)$ to $(C)($ through $B)$