If left| {z - 3i} right| le 5 , then minimum value of | z + 2 | is equal to

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4-1.Complex numbers

normal

If $\left| {z - 3i} \right| \le 5$ , then minimum value of $| z + 2 |$ is equal to

A

$0$

B

$2$

C

$5-\sqrt {13}$

D

$1$

Solution

let $z+2=z^{\prime}$

$\left|z^{\prime}-2-3 i\right| \leq 5$

$\Rightarrow\left|z^{\prime}\right|_{\min }=0$

Standard 11

Mathematics

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