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3.Trigonometrical Ratios, Functions and Identities
medium
જો $sin\theta_1 + sin\theta_2 + sin\theta_3 = 3,$ થાય તો $cos\theta_1 + cos\theta_2 + cos\theta_3=$
A
$3$
B
$2$
C
$1$
D
$0$
Solution
Since $\sin \theta_{1}+\sin \theta_{2}+\sin \theta_{3}=3$
$\therefore \quad \sin \theta_{1}=\sin \theta_{2}=\sin \theta_{3}=1$
$\Rightarrow \quad \theta_{1}=\theta_{2}=\theta_{3}=\frac{\pi}{2}$
$ \therefore \quad \cos \theta_{1}=\cos \theta_{2}=\cos \theta_{3}=0 $
$ \therefore \quad \cos \theta_{1} =\cos \theta_{2}=\cos \theta_{3}=0 $
Standard 11
Mathematics