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2. Polynomials
medium
જો $p(x)=x^{2}-4 x+3$ તો $p(2)-p(-1)+p\left(\frac{1}{2}\right)$ મેળવો:
A
$\frac{31}{4}$
B
$\frac{-30}{5}$
C
$\frac{-32}{4}$
D
$\frac{-31}{4}$
Solution
We have $p(x)=x^{2}-4 x+3$
$\therefore p(2)-p(-1)+p\left(\frac{1}{2}\right)=\left(2^{2}-4 \times 2+3\right)-\left\{(-1)^{2}-4(-1)+3\right\}+\left\{\left(\frac{1}{2}\right)^{2}-4 \times \frac{1}{2}+3\right\}$
$=(4-8+3)-(1+4+3)+\left(\frac{1}{4}-2+3\right)$
$=-1-8+\frac{5}{4}$
$=-9+\frac{5}{4}=\frac{-36+5}{4}=\frac{-31}{4}$
Standard 9
Mathematics
