8. Introduction to Trigonometry
easy

જો $3 \cot \theta=4,$ તો $\frac{1-\tan ^{2} \theta}{1+\tan ^{2} \theta}=\ldots \ldots \ldots \ldots$

A

$\frac{7}{25}$

B

$\frac{4}{3}$

C

$\frac{3}{4}$

D

$\frac{1}{7}$

Solution

$3 \cot \theta=4\, \therefore \cot \theta=\frac{4}{3}\, \therefore \tan \theta=\frac{3}{4}$

$\frac{1-\tan ^{2} \theta}{1+\tan ^{2} \theta}=\frac{1-\left(\frac{3}{4}\right)^{2}}{1+\left(\frac{3}{4}\right)^{2}}=\frac{1-\frac{9}{16}}{1+\frac{9}{16}}=\frac{16-9}{16+9}=\frac{7}{25}$

Standard 10
Mathematics

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