If {{a{x^2} + bx + c} over {(x - 1),(x + 2),(2x + 3)}} = {3 over {x - 1}} + {2 over {x + 2}} - {5 ov

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Basic of Logarithms

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If ${{a{x^2} + bx + c} \over {(x - 1)\,(x + 2)\,(2x + 3)}}$=${3 \over {x - 1}} + {2 \over {x + 2}} - {5 \over {2x + 3}}$, then

A

$a = 5$

B

$b = - 18$

C

$c = 20$

D

None of these

Solution

(a) $a{x^2} + bx + c = 3(x + 2)\,(2x + 3) + 2(x – 1)\,(2x + 3)$
$-5(x – 1)(x + 2)$

$ \Rightarrow $ $a = 6 + 4 – 5 = 5$, $b = 21 + 2 – 5 = 18$,

$c = 18 – 6 + 10 = 22$.

Standard 11

Mathematics

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