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Basic of Logarithms
easy
જો ${{1 - \cos x} \over {\cos x(1 + \cos x)}} = {{\sin \alpha } \over {\cos x}} - {2 \over {1 + \cos x}}$, તો $\alpha = $
A
$\pi\over 8$
B
$\pi\over 4$
C
$\pi\over 2$
D
$\pi $
Solution
(c) $1 – \cos x = \sin \alpha (1 + \cos x) – 2\cos x$
$ \Rightarrow $$1 = \sin \alpha ,\,\, – 1 = – 2 + \sin \alpha $$ \Rightarrow $$\alpha = {\pi \over 2}$.
Standard 11
Mathematics
