3 and 4 .Determinants and Matrices
easy

If $A = \left[ {\begin{array}{*{20}{c}}1&3&0\\{ - 1}&2&1\\0&0&2\end{array}} \right],B = \left[ {\begin{array}{*{20}{c}}2&3&4\\1&2&3\\{ - 1}&1&2\end{array}} \right]$, then $AB =$

A

$\left[ {\begin{array}{*{20}{c}}5&9&{13}\\{ - 1}&2&4\\{ - 1}&2&4\end{array}} \right]$

B

$\left[ {\begin{array}{*{20}{c}}5&9&{13}\\{ - 1}&2&4\\{ - 2}&2&4\end{array}} \right]$

C

$\left[ {\begin{array}{*{20}{c}}1&2&4\\{ - 1}&2&4\\{ - 2}&2&4\end{array}} \right]$

D

None of these

Solution

(b) $AB = \left[ {\begin{array}{*{20}{c}}{\,\,5}&9&{13}\\{ – 1}&2&4\\{\,\, – 2}&2&4\end{array}} \right]$.

Standard 12
Mathematics

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