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3.Trigonometrical Ratios, Functions and Identities
easy
If $\sin \theta = - \frac{1}{{\sqrt 2 }}$ and $\tan \theta = 1,$ then $\theta $ lies in which quadrant
A
First
B
Second
C
Third
D
Fourth
Solution
(c) $\sin \theta = – \frac{1}{{\sqrt 2 }}$ and $\tan \theta = 1$
$ \Rightarrow $$\sin \theta = \sin 225^\circ \Rightarrow \theta = 225^\circ $
Since $\sin \theta $ is $ – ve$ and $\tan \theta $is $ + ve$ in third quadrant.
Standard 11
Mathematics
