Gujarati
11.Thermodynamics
medium

If $\gamma = 2.5$ and volume is equal to $\frac{1}{8}$ times to the initial volume then pressure $P' $ is equal to (Initial pressure $= P$)

A

$P' = P$

B

$P' = 2P$

C

$P' = P \times {(2)^{15/2}}$

D

$P' = 7P$

Solution

(c)$\frac{{{P_2}}}{{{P_1}}} = {\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^\gamma } \Rightarrow \frac{{P'}}{P} = {(8)^{5/2}} \Rightarrow P' = P \times {(2)^{15/2}}$

Standard 11
Physics

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