If $\gamma = 2.5$ and volume is equal to $\frac{1}{8}$ times to the initial volume then pressure $P' $ is equal to (Initial pressure $= P$)
If $\gamma = 2.5$ and volume is equal to $\frac{1}{8}$ times to the initial volume then pressure $P' $ is equal to (Initial pressure $= P$)
- A
$P' = P$
- B
$P' = 2P$
- C
$P' = P \times {(2)^{15/2}}$
- D
$P' = 7P$
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