1.Units, Dimensions and Measurement
medium

If $C$ and $L$ denote capacitance and inductance respectively, then the dimensions of $LC$ are

A${M^0}{L^0}{T^0}$
B${M^0}{L^0}{T^2}$
C${M^2}{L^0}{T^2}$
D$ML{T^2}$

Solution

(b) $f = \frac{1}{{2\pi \sqrt {LC} }} \Rightarrow LC = \frac{1}{{{f^2}}} = [{M^0}{L^0}{T^2}]$
Standard 11
Physics

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