Gujarati
3.Trigonometrical Ratios, Functions and Identities
medium

If $\tan \,(A - B) = 1,\,\,\,\sec \,(A + B) = \frac{2}{{\sqrt 3 }},$ then the smallest positive value of $B$ is

A

$\frac{{25}}{{24}}\pi $

B

$\frac{{19}}{{24}}\pi $

C

$\frac{{13}}{{24}}\pi $

D

$\frac{{11}}{{24}}\pi $

Solution

(b) $\tan (A – B) = 1 \Rightarrow A – B = \frac{\pi }{4}$…..(i)

and $\sec (A + B) = \frac{2}{{\sqrt 3 }} \Rightarrow A + B = \frac{{11\pi }}{6}$…..(ii)

from (i) and (ii),

$ \Rightarrow B = \frac{{19\pi }}{{24}}$.

Standard 11
Mathematics

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