If h is Planck’s constant is SI system, | vedclass

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Question

Momentum of photo, $p=\frac{E}{c}=\frac{h 
u}{c}$ where $\mathrm{E}$ is the energy of a photon and $\mathrm{c}$ is the velocity of light.
$	herefor

Vedclass · Accepted Answer

$10^{12} \,h$

Vedclass · Answer

Momentum of photo, $p=\frac{E}{c}=\frac{h 
u}{c}$ where $\mathrm{E}$ is the energy of a photon and $\mathrm{c}$ is the velocity of light.
$	herefore p=\frac{h c}{c \lambda} \quad\left[\because 
u=\frac{c}{\lambda}ight]$
$p=\frac{h}{\lambda}=\frac{h}{0.01 	imes 10^{-10}}=10^{12} h$

If $h$ is Planck’s constant is $SI$ system, the momentum of a photon of wavelength $0.01\, \mathring A $ is:

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