If $\left| {z – 3 + 2i} \right| \leq 4$ then the difference between the greatest value and the least value of $\left| z \right|$ is

If $x = 3 + i$, then $x^3 – 3x^2 – 8x + 15 = $

Let the complex number $z=x+$ iy be such that $\frac{2 z-3 i}{2 z+i}$ is purely imaginary. If $x + y ^2=0$, then $y^4+y^2-y$ is equal to :

The imaginary part of $(3+2 \sqrt{-54})^{1 / 2}-(3-2 \sqrt{-54})^{1 / 2}$ can be

Solve the equation $\sqrt{2} x^{2}+x+\sqrt{2}=0$