2.Motion in Straight Line
easy

$15\, m/s$ વેગથી ઉપર તરફ ફેંકતા કેટલી......$m$ ઊંચાઇ પર જશે? $(g = 10\, m/s^2)$

A

$11.25 $

B

$16.2$

C

$24.5$

D

$7.62 $

Solution

(a) ${h_{\max }} = \frac{{{u^2}}}{{2g}} = \frac{{{{(15)}^2}}}{{2 \times 10}} = 11.25\;m$.

Standard 11
Physics

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