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4.Principles of Inheritance and Variation
medium
If a colourblind man marries a woman who is homozygous for normal colour vision, the probability of their son being colourblind is
A
$0$
B
$0.5$
C
$0.75$
D
$1$
(NEET-2016)
Solution
(a): Genotype of colour blind man -$X^c Y$
Genotype of women homozygous -$XX$ for normal woman
Hence, there is zero $(0)$ probability of their son to be colour-blind.
Standard 12
Biology