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यदि एक $^{\prime}$लक्षण - $A ^{\prime}$ अलैंगिक प्रजनन वाली समष्टि के $10$ प्रतिशत सदस्यों में पाया जाता है तथा $^{\prime}$लक्षण - $B ^{\prime}$ उसी समष्टि में $60$ प्रतिशत जीवों में पाया जाता है, तो कौन सा लक्षण पहले उत्पन्न हुआ होगा?
Solution
In asexual reproduction, the reproducing cells produce a copy of their $DNA$ through some chemical reactions. However, this copying of $DNA$ is not accurate and therefore, the newly formed $DNA$ has some variations.
It can be easily observed in the above figure that in asexual reproduction, very few variations are allowed. Therefore, if a trait is present in only $10\%$ of the population, it is more likely that the trait has arisen recently. Hence, it can be concluded that trait $B$ that exists in $60\%$ of the same population has arisen earlier than trait $A$.
