If one mole of an ideal gas goes through process A → B and B → C . Given that T _{ A }=400, K ,

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11.Thermodynamics

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If one mole of an ideal gas goes through the process $A \rightarrow B$ and $B \rightarrow C .$ Given that $T _{ A }=400\, K ,$ and $T _{ C }=400 \,K .$ If $\frac{ P _{ B }}{ P _{ A }}=\frac{1}{5},$ then find the heat supplied to the gas (in $J$)

A

$2059.2$

B

$3659.2$

C

$2225.2$

D

$2659.2$

(AIIMS-2019)

Solution

The expression to calculate the heat supply to the gas is give as,

$\Delta Q = n \Delta T \left( C _{ p }- C _{ v }\right)$

Substitute the values.

$\Delta Q = n \Delta T \left( C _{ p }- C _{ v }\right)$

$=1 \times 8.31 \times\left(400-\frac{400}{5}\right)$

$=2659.2 J$

Standard 11

Physics

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