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4.Average
medium
If the average of $m$ numbers is $n^{2}$ and that of $n$ numbers is $m^{2},$ then the average of $( m + n )$ numbers is
A
$\frac{m}{n}$
B
$m+n$
C
$m n$
D
$m-n$
Solution
Sum of m numbers $=n^{2} \times m$
Sum of n numbers $=m^{2} \times n$
Average of $(m+n)=\frac{n^{2} \times m+m^{2} \times n}{m+n}=\frac{m n(n+m)}{(n+m)}=m n$
Standard 13
Quantitative Aptitude
