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3.Current Electricity
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If the balance point is obtained at the $35^{th} cm$ in a meter bridge the resistances in the left and right gaps are in the ratio of
A
$7 : 13$
B
$13 : 7$
C
$9 : 11$
D
$11 : 9$
Solution
(a) Using Wheatstone principle $\frac{P}{Q} = \frac{R}{S} = \frac{R}{{100 – l}}$
$ = \frac{{35}}{{100 – 35}} = \frac{{35}}{{65}} = \frac{7}{{13}}$
Standard 12
Physics
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