If charge on a capacitor is increased by 2 coulomb, energy stored in it increases by 21% . original

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2. Electric Potential and Capacitance

medium

If the charge on a capacitor is increased by $2$ coulomb, the energy stored in it increases by $21\%$. The original charge on the capacitor is....$C$

$10$

$20$

$30$

$40$

Solution

Percentage increase in energy of capacitor $=\frac{\frac{q_{f}^{2}}{2 C}-\frac{q_{i}^{2}}{2 C}}{\frac{q_{i}^{2}}{2 C}} \times 100=21$ and $q_{f}-q_{i}=2$

Solving, we get $q_{i}=20 C$

Standard 12

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