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11.Dual Nature of Radiation and matter
easy
If the energy of the photon is increased by a factor of $4$, then its momentum
A
Does not change
B
Decreases by a factor of $4$
C
Increases by a factor of $4$
D
Decreases by a factor of $2$
Solution
(c) $P = \frac{h}{\lambda },\;E = \frac{{hc}}{\lambda }$
==> $E = Pc.$
Standard 12
Physics