Gujarati
11.Dual Nature of Radiation and matter
easy

If the energy of the photon is increased by a factor of $4$, then its momentum

A

Does not change

B

Decreases by a factor of $4$

C

Increases by a factor of $4$

D

Decreases by a factor of $2$

Solution

(c) $P = \frac{h}{\lambda },\;E = \frac{{hc}}{\lambda }$

==> $E = Pc.$

Standard 12
Physics

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