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3 and 4 .Determinants and Matrices
easy
જો શ્રેણિક $\left[ {\begin{array}{*{20}{c}}0&1&{ - 2}\\{ - 1}&0&3\\\lambda &{ - 3}&0\end{array}} \right]$ એ અસામાન્ય શ્રેણિક તો $\lambda $ =
A
$-2$
B
$-1$
C
$1$
D
$2$
Solution
(d) The matrix $A = \left[ {\begin{array}{*{20}{c}}{\,\,0}&{\,\,1}&{ – 2}\\{ – 1}&{\,\,0}&{\,\,3}\\{\,\,\lambda }&{ – 3}&{\,\,0}\end{array}} \right]$ is singular
$|A|$ = 0 ==> $0 – 1( – 3\lambda ) + ( – 2)(3) = 0$
$ \Rightarrow 3\lambda – 6 = 0 \Rightarrow \lambda = 2$.
Standard 12
Mathematics