If the ratio of C.I. & S.I. interest for | vedclass

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Question

Here, $C I=P\left[\left(1+\frac{R}{100}\right)^{2}-1\right]$

$=P\left[\left(1+\frac{R^{2}}{(100)^{2}}+\frac{2 R}{100}\right)-1\right]=\frac{P R}{10

Vedclass · Accepted Answer

$40$

Vedclass · Answer

Here, $C I=P\left[\left(1+\frac{R}{100}ight)^{2}-1ight]$

$=P\left[\left(1+\frac{R^{2}}{(100)^{2}}+\frac{2 R}{100}ight)-1ight]=\frac{P R}{100}\left[\frac{R}{100}+2ight]$

$\Rightarrow S I=\frac{P 	imes 2 	imes R}{100} \Rightarrow \frac{C I}{S I}=1.2=\frac{\frac{P R}{100}\left[\frac{R+200}{100}ight]}{\frac{2 P R}{100}}$

$\Rightarrow \frac{ CI }{ SI }=\frac{200+ R }{200} \Rightarrow 1.2=\frac{200+ R }{200} \Rightarrow R =40 \%$

If the ratio of $C.I. \& S.I.$ interest for the same principal and rate of interest for $2$ years is $1.2,$ find the rate of interest (In $\%$)

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