If the volume of a block of metal changes by | vedclass

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Question

since, $\gamma=\frac{\Delta V}{V \Delta T}$av

$\Rightarrow \quad \gamma=\frac{0.12}{100} 	imes \frac{1}{20}$

$\Rightarrow \quad \gamma=6 	imes

Vedclass · Accepted Answer

$2 &times; 10^{-5}$

Vedclass · Answer

since, $\gamma=\frac{\Delta V}{V \Delta T}$av

$\Rightarrow \quad \gamma=\frac{0.12}{100} 	imes \frac{1}{20}$

$\Rightarrow \quad \gamma=6 	imes 10^{-5} /^{0} C$

$	herefore \quad \alpha=\frac{\gamma}{3}$

$\Rightarrow \alpha=\frac{6 	imes 10^{-5}}{3}$

$=2.0 	imes 10^{-5} /^{0} \mathrm{C}$

S.No.	$l(m)$	$\Delta T{(^o}C)$	$\Delta l(m)$
$(1)$	$2$	$10$	$4\times 10^{-4}$
$(2)$	$1$	$10$	$4\times 10^{-4}$
$(3)$	$2$	$20$	$2\times 10^{-4}$
$(4)$	$3$	$10$	$6\times 10^{-4}$

If the volume of a block of metal changes by $0.12 \%$ when it is heated thrugh $20^oC$, the coefficient of linear expansion (in $^oC^{-1}$) of the metal is

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