In O₂^ - , {O₂} and O₂^{ - 2} molecular species, total number of antibonding electrons respect

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4.Chemical Bonding and Molecular Structure

medium

In $O_2^ - ,$ ${O_2}$ and $O_2^{ - 2}$ molecular species, the total number of antibonding electrons respectively are

$7, 6, 8$

$1, 0, 2$

$6, 6, 6$

$8, 6, 8$

Solution

(a) Molecular orbital electronic configuration of these species are :

$O_2^ – (17{e^ – }) = $$\sigma 1{s^2}{\sigma ^*}1{s^2},\sigma 2{s^2}{\sigma ^*}2{s^2},\sigma 2{p_x}^2,\pi 2{p_y}^2,$ $\pi 2{p_z}^2,{\pi ^*}2{p_y}^2{\pi ^*}2{p_z}^1$

${O_2}(16e) = $$\sigma 1{s^2}{\sigma ^*}1{s^2},\sigma 2{s^2}{\sigma ^*}2{s^2},\sigma 2{p_x}^2,\pi 2{p_y}^2,$$\pi 2{p_z}^2{\pi ^*}2{p_y}^1

{\pi ^*}2{p_z}^1$

$O_2^{2 – }(18e) = $ $\sigma 1{s^2}{\sigma ^*}1{s^2},\sigma 2{s^2}{\sigma ^*}2{s^2},\sigma 2{p_x}^2,\pi 2{p_y}^2,$ $\pi 2{p_z}^2{\pi ^*}2{p_y}^2{\pi ^*}2{p_z}^2$

Hence number of antibonding electrons are $7,6,$ and $8$ respectively.

Standard 11

Chemistry