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In $O_2^ - ,$ ${O_2}$ and $O_2^{ - 2}$ molecular species, the total number of antibonding electrons respectively are
$7, 6, 8$
$1, 0, 2$
$6, 6, 6$
$8, 6, 8$
Solution
(a) Molecular orbital electronic configuration of these species are :
$O_2^ – (17{e^ – }) = $$\sigma 1{s^2}{\sigma ^*}1{s^2},\sigma 2{s^2}{\sigma ^*}2{s^2},\sigma 2{p_x}^2,\pi 2{p_y}^2,$ $\pi 2{p_z}^2,{\pi ^*}2{p_y}^2{\pi ^*}2{p_z}^1$
${O_2}(16e) = $$\sigma 1{s^2}{\sigma ^*}1{s^2},\sigma 2{s^2}{\sigma ^*}2{s^2},\sigma 2{p_x}^2,\pi 2{p_y}^2,$$\pi 2{p_z}^2{\pi ^*}2{p_y}^1
{\pi ^*}2{p_z}^1$
$O_2^{2 – }(18e) = $ $\sigma 1{s^2}{\sigma ^*}1{s^2},\sigma 2{s^2}{\sigma ^*}2{s^2},\sigma 2{p_x}^2,\pi 2{p_y}^2,$ $\pi 2{p_z}^2{\pi ^*}2{p_y}^2{\pi ^*}2{p_z}^2$
Hence number of antibonding electrons are $7,6,$ and $8$ respectively.
