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In $Fig.$ $LM$ is a line parallel to the $y$ - axis at a distance of $3$ units.
$(i)$ What are the coordinates of the points $P , R$ and Q?
$(ii)$ What is the difference between the abscissa of the points $L$ and $M ?$
Solution
$(i)$ Clearly, the distance of $P$ from $y$ -axis is 3 units and that of from $x$ -axis is $2$ units. since $P$ lies in the first quadrant, so its coordinate are $(3,2)$ Point $R$ lies on $x$ – axis and its distance from $y$ and $x$ -axes are $3$ and $0$ units respectively.
So, its coordinates are $(3,0)$ Clearly, point $Q$ lies in the fourth quadrant. The distance of $Q$ from $y$ -axis is $3$ units and from $x$ -axis is $1$ unit.
So, the coordinates of $Q(3,-1)$
$(ii)$ From the given figure (graph), we find that the points $L$ and $M$ lie on the same straight line. So, $L$ and $M$ are collinear.
Hence, the difference between the abscissa of the points $L$ and $M$ is $0 .$
