In Delta ABC , m ∠ A =90, AB =5, AC =12 and BC =13 . ∴ sin C +cos C =ldots ldots ldots ldots

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8. Introduction to Trigonometry

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In $\Delta ABC , m \angle A =90, AB =5, AC =12$ and $BC =13 .$ $\therefore \sin C +\cos C =\ldots \ldots \ldots \ldots$

A

$1$

B

$\frac{7}{13}$

C

$5$

D

$\frac{17}{13}$

Solution

$\sin C =\frac{ AB }{ BC }=\frac{5}{13} $ and $\cos C =\frac{ AC }{ BC }=\frac{12}{13}$

$\therefore \sin C+\cos C=\frac{5}{13}+\frac{12}{13}=\frac{17}{13}$

Standard 10

Mathematics

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