In $a$ one dimensional collision between two identical particles $A$ and $B, B$ is stationary and $A$ has momentum $p$ before impact. During impact, $B$ gives impulse $J$ to $A.$
The total momentum of the $‘A$ plus $B’$ system is $p$ before and after the impact, and $(p-J)$ during the impact.
During the impact $A$ gives impulse $J$ to $ B$
The coefficient of restitution is $\frac{{2J}}{p} - 1$
Both $(B)$ and $(C)$
The quantity that is not conserved in an inelastic collision is
Explain the total linear momentum is conserved in an elastic collision and also explain the inelastic collision and completely elastic collision.
Two identical balls $P$ and $Q$ moving in the $x-y$ plane collide at the origin $(x=0,y=0)$ of the coordinate system. Their velocity components just before the moment of impact were, for ball $P$, $v_x=6\ m/s$, $v_y=0$; for ball $Q$, $v_x=-5\ m/s$, $v_y=2\ m/s$. As a result of the collision, the ball $P$ comes to rest. The velocity components of the ball $Q$ just after collision will be
A particle of mass $m$ is moving along the $x$ -axis with initial velocity $u \hat i$. It collides elastically with a particle of mass $10\, m$ at rest and then moves with half its initial kinetic energy (see figure). If $\sin \theta_{1}=\sqrt{n} \sin \theta_{2}$ then value of $n$ is.....
As shown in the figure $a$ body of mass $m$ moving vertically with speed $3\, m/s$ hits a smooth fixed inclined plane and rebounds with a velocity $v_f$ in the horizontal direction. If $\angle$ of inclined is $30^o$, the velocity $v_f$ will be