In a meter bridge experiment, initially jockey is at null point. Now resistance R₁ & R?

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3.Current Electricity

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In a meter bridge experiment, initially the jockey is at null point. Now resistance $R_1$ $\&$ $R_2$ is interchanged. Shift in the position of jockey is ................ $cm$

A

$20$

B

$30$

C

$40$

D

$50$

Solution

Initially $\frac{\mathrm{R}_{1}}{\mathrm{R}_{2}}=\frac{2}{3}=\frac{\ell}{100-\ell} \Rightarrow \ell=40 \mathrm{\,cm}$

Now $\frac{\mathrm{R}_{2}}{\mathrm{R}_{1}}=\frac{3}{2}=\frac{\ell}{100-\ell} \Rightarrow \ell=60 \mathrm{\,cm}$

shift $=20 \mathrm{\,cm}$

Standard 12

Physics

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