3.Current Electricity
hard

In a meter bridge experiment null point is obtained at $40\, cm$ from one end of the wire when resistance $X$ is balanced against another resistance $Y$. If $X < Y$, then the new position of the null point from the same end, if one decides to balance a resistance of $3X$ against $Y$, will be close to .............. $cm$

A

$80$

B

$75$

C

$67$

D

$50$

(JEE MAIN-2013)

Solution

From question, $\frac{x}{y}=\frac{40}{100-40}=\frac{2}{3}$

$\Rightarrow x=\frac{2}{3} y$

Again, $\frac{3 x}{y}=\frac{z}{100-z}$

or $\frac{3 \times \frac{2 y}{3}}{y}=\frac{z}{100-z}$

Solving we get $Z=67\, \mathrm{cm}$

Therefore new position of null point

$\cong 67\, \mathrm{cm}$

Standard 12
Physics

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