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In a Rutherford scattering experiment when a projectile of charge $z_1$ and mass $M_1$ approaches a target nucleus of charge $z_2$ and mass $M_2$, the distance of closest approach is $r_0$ The energy of the projectile is
A
directly proportional to $Z_1 Z_2$
B
inversely proportional to $Z_1$
C
directly proportional to $m_1\times m_2 $
D
directly proportional to mass $m_1 $
(AIPMT-2009)
Solution
Energy of the projectile is the potential energy at closest approach, $\frac{1}{4 \pi \varepsilon_{0}} \frac{z_{1} z_{2}}{r}$
Therefore energy $\propto z_{1} z_{2}$.
Standard 12
Physics
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