In a simple pendulum, the period of oscillation $T$ is related to length of the pendulum $l$ as

The period of simple pendulum is measured as $T$ in a stationary lift. If the lift moves upwards with an acceleration of $5\, g$, the period will be

If the length of the simple pendulum is increased by $44\%$, then what is the change in time period of pendulum ..... $\%$

A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is $4 \mathrm{~m}$, then the time period of small oscillations will be ____ $s$. $\left[\right.$ take $\left.\mathrm{g}=\pi^2 \mathrm{~ms}^{-2}\right]$

A simple pendulum has time period $T_1$. The point of suspension is now moved upward according to equation $y = k{t^2}$ where $k = 1\,m/se{c^2}$. If new time period is $T_2$ then ratio $\frac{{T_1^2}}{{T_2^2}}$ will be

In a seconds pendulum, mass of bob is $30\, g$. If it is replaced by $90\, g$ mass. Then its time period will be ... $\sec$