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5.Magnetism and Matter
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In a tangent galvanometer a current of $0.1 \,A $ produces a deflection of $30^o$. The current required to produce a deflection of $60^o$ is......$A$
A
$0.2$
B
$0.3 $
C
$0.4 $
D
$0.5$
Solution
(b)$i \propto \tan \phi \Rightarrow \frac{{{i_1}}}{{{i_2}}} = \frac{{\tan {\phi _1}}}{{\tan {\phi _2}}}$
$ \Rightarrow \frac{{0.1}}{{{i_2}}} = \frac{{\tan 30^\circ }}{{\tan 60^\circ }} = \frac{1}{3} \Rightarrow {i_2} = 0.3\,A$
Standard 12
Physics
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