Gujarati
5.Magnetism and Matter
medium

In a tangent galvanometer a current of $0.1 \,A $ produces a deflection of $30^o$. The current required to produce a deflection of $60^o$ is......$A$

A

$0.2$

B

$0.3 $

C

$0.4 $

D

$0.5$

Solution

(b)$i \propto \tan \phi \Rightarrow \frac{{{i_1}}}{{{i_2}}} = \frac{{\tan {\phi _1}}}{{\tan {\phi _2}}}$
$ \Rightarrow \frac{{0.1}}{{{i_2}}} = \frac{{\tan 30^\circ }}{{\tan 60^\circ }} = \frac{1}{3} \Rightarrow {i_2} = 0.3\,A$

Standard 12
Physics

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