In an AC circuit potential differences across an inductance and resistance joined in series are resp

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7.Alternating Current

medium

In an $AC$ circuit the potential differences across an inductance and resistance joined in series are respectively $16\,V$ and $20\,V$. The total potential difference of the source is..........$V$

$20$

$25.6$

$31.9$

$53.5$

(AIIMS-2007)

Solution

In any ac $(LR)$ circuit, total potential is given by $\mathrm{V}=\sqrt{\mathrm{V}_{\mathrm{R}}^{2}+\mathrm{V}_{\mathrm{L}}^{2}}$ where $\mathrm{V}_{\mathrm{R}}$ and $\mathrm{V}_{\mathrm{L}}$

are potential across resistance and inductance respectively.

Hence $V=\sqrt{(16)^{2}+(20)^{2}}=\sqrt{256+400}$

$=25.6 \,V$

Standard 12

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hard

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medium

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$Image$

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