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7.Gravitation
medium
In an orbit if the time of revolution of a satellite is $T$, then $P E$ is proportional to
A
$T^{1 / 3}$
B
$T^3$
C
$T^{-2 / 3}$
D
$T^{-4 / 3}$
Solution
(c)
$P E=-\frac{G M M}{\gamma}$
$T^2 \propto \gamma^3$
$P E=\frac{C}{\gamma}-(1)$
$T^2=kr^3$
$T^2=K\left(\frac{C}{P E}\right)^3$
$T^2=\frac{A}{(P E)^3}$
$(P E)^3= \frac{A}{T^2}$
$P E=\frac{A^{1 / 3}}{T^{2 / 3}}$
$P E \propto \frac{1}{-T^{2 / 3}}$
$P E \propto T^{\frac{-2}{3}}$
Standard 11
Physics
