In HardyWeinberg equation, frequency of heterozygous individual is represented by

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6.Evolution

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In HardyWeinberg equation, the frequency of heterozygous individual is represented by

$p^2$

$2pq$

$pq$

$q^2$

(NEET-2016)

Solution

(b) : In a stable population, for a gene with two alleles, ‘$A$’ (dominant) and ‘$a$’ (recessive), if the frequency of ‘$A$’ is $p$ and the frequency of ‘$a$’ is $q$, then the frequencies of the three possible genotypes ($AA, Aa$ and $aa$) can be expressed by the Hardy Weinberg equation :

$p^2 + 2pq + q^2 = 1$

where $p^2$ = Frequency of $AA$ (homozygous dominant) individuals

$q^2$ = Frequency of $aa$ (homozygous recessive) individuals

$2pq$ = Frequency of $Aa$ (heterozygous) individuals

Standard 12

Biology