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6.Evolution
medium
In HardyWeinberg equation, the frequency of heterozygous individual is represented by
A
$p^2$
B
$2pq$
C
$pq$
D
$q^2$
(NEET-2016)
Solution
(b) : In a stable population, for a gene with two alleles, ‘$A$’ (dominant) and ‘$a$’ (recessive), if the frequency of ‘$A$’ is $p$ and the frequency of ‘$a$’ is $q$, then the frequencies of the three possible genotypes ($AA, Aa$ and $aa$) can be expressed by the Hardy Weinberg equation :
$p^2 + 2pq + q^2 = 1$
where $p^2$ = Frequency of $AA$ (homozygous dominant) individuals
$q^2$ = Frequency of $aa$ (homozygous recessive) individuals
$2pq$ = Frequency of $Aa$ (heterozygous) individuals
Standard 12
Biology
