In how many years will a sum of ₹ 800 at 10 % | vedclass

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Question

Let the required number of years be $N$.

$	herefore \quad 800\left(1+\frac{10}{200}ight)^{2 N}=926.10$

i.e. $\quad 800\left(\frac{105}{100}

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

Let the required number of years be $N$.

$	herefore \quad 800\left(1+\frac{10}{200}ight)^{2 N}=926.10$

i.e. $\quad 800\left(\frac{105}{100}ight)^{2 N}=926.10$

$800\left(\frac{21}{20}ight)^{2 N}=926.10$

$	herefore$

$\begin{aligned}\left(\frac{21}{20}ight)^{2 N} &=\frac{926.10}{800} \&=\frac{9261}{8000} \&=\left(\frac{21}{20}ight)^{3}\end{aligned}$

$	herefore$

$2 N=3$ years

or $N=1 \frac{1}{2}$ years

In how many $years$ will a sum of ₹ $800$ at $10 \%$ per annum compounded semi-annually become ₹ $926.10$?

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