Gujarati
11.Thermodynamics
easy

In the $P-V$ diagram shown in figure $ABC$ is a semicircle. The work done in the process $ABC$ is

A

Zero

B

$\frac{\pi }{2}atm - lt$

C

$ - \frac{\pi }{2}atm - lt$

D

$4 atm-lt$

Solution

(b) ${W_{AB}}$ is negative (volume is decreasing) and

${W_{BC}}$ is positive (volume is increasing) and

since, $\left| {\,{W_{BC}}} \right|\, > \,\left| {\,{W_{AB}}} \right|$

$\therefore $ net work done is positive and area between semicircle which is equal to $\frac{\pi }{2}atm – lt.$

Standard 11
Physics

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