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11.Thermodynamics
easy
In the $P-V$ diagram shown in figure $ABC$ is a semicircle. The work done in the process $ABC$ is

A
Zero
B
$\frac{\pi }{2}atm - lt$
C
$ - \frac{\pi }{2}atm - lt$
D
$4 atm-lt$
Solution
(b) ${W_{AB}}$ is negative (volume is decreasing) and
${W_{BC}}$ is positive (volume is increasing) and
since, $\left| {\,{W_{BC}}} \right|\, > \,\left| {\,{W_{AB}}} \right|$
$\therefore $ net work done is positive and area between semicircle which is equal to $\frac{\pi }{2}atm – lt.$
Standard 11
Physics
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