In arrangement shown in figure, pulleys are massless and frictionless and threads are inextensible.

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4-1.Newton's Laws of Motion

hard

In the arrangement shown in figure, pulleys are massless and frictionless and threads are inextensible. The Block of mass $m_1$ will remain at rest, if

A$\frac{4}{m_1}=\frac{1}{m_2}+\frac{1}{m_3}$

B$\frac{1}{m_1}=\frac{1}{m_2}+\frac{1}{m_3}$

C$m_1=m_2+m_3$

D$\frac{1}{m_3}=\frac{2}{m_2}+\frac{3}{m_1}$

Solution

$2 T = m _1 g$
$m _2 g- T = m _2 a$
$T – m _3 g = m _3 a$
on solving
$\frac{4}{m_1}=\frac{1}{m_2}+\frac{1}{m_3}$

Standard 11

Physics

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(JEE MAIN-2022)