- Home
- Standard 12
- Chemistry
In the extraction of copper from its sulphide ore, the metal is formed by reduction of $Cu_2O$ with
$FeS$
$CO$
$Cu_2S$
$SO_2$
Solution
In the extraction of copper from its sulphide ore, the metal is formed by reduction of $Cu _2 O$ with $Cu _2 S$.
The sulphide ore of copper is heated in air until a part is converted to oxide and then further heating in the absence of air to let the oxide react with unchanged sulphide.
Self-reduction of $CuS$ to $Cu$ can be carried out in either Bessemer converter or Pierce-Smith converter.
$2 Cu _2 S +3 O _2 \rightarrow 2 Cu _2 O +2 SO _2$
$2 Cu _2 O + Cu _2 S \rightarrow 6 Cu + SO _2$
Similar Questions
Match column $(I)$ (process) with column $(II)$ (electrolyte)
| $(I)$ (process) | $(II)$ (electrolyte) |
| $(i)$ Downs cell | $(W)$ fused $MgCl_2$ |
| $(ii)$ Dow sea water process | $(X)$ fused $(Al_2O_3+Na_3AlF_6)$ |
| $(iii)$ Hall – Heroult | $(Y)$ fused $KHF_2$ |
| $(iv)$ Moissam | $(Z)$ fused $(40\%\,NaCl\,+\,60\%\,CaCl_2)$ |
Choose the correct alternate :
Match Column $-I$ with Column $-II$ and select the correct answer using the codes given below.
| Column $-I$ | Column $-II$ |
| $(i)$ Iron and copper | $(P)$ Poling |
| $(ii)$ Zirconium and Titanium | $(Q)$ Bessemerisation |
| $(iii)$ Lead and Tin | $(R)$ Van – arkel |
| $(iv)$ Copper and Tin | $(S)$ Liquation |
