In the following figure $r_1$ and $r_2$ are $5\,cm$ and $30\,cm$ respectively. If the moment of inertia of the wheel is $1500\,kg\,m^2$ then its angular acceleration will be (Approximately)
$2\times 10^{-4}\,rad/s^2$
$3\times 10^{-3}\,rad/s^2$
$4\times 10^{-2}\,rad/s^2$
$5\times 10^{-1}\,rad/s^2$
The plank in the figure moves a distance $100\,mm$ to the right while the centre of mass of the sphere of radius $150\, mm$ moves a distance $75\,mm$ to the left. The angular displacement of the sphere (in radian) is (there is no slipping anywhere) :-
The linear mass density of a rod of length $L$ varies as $\lambda = kx^2$, where $k$ is a constant and $x$ is the distance from one end. The position of centre of mass of the rod is
The centre of mass of a body
A uniform rod of mass $m$ and length $l$ rotates in a horizontal plane with an angular velocity $\omega $ about a vertical axis passing through one end. The tension in the rod at a distance $x$ from the axis is
A thin wire of length $\ell$ and mass $m$ is bent in the form of a semicircle as shown. Its moment of inertia about an axis joining its free ends will be ...........