Let $A, B,$ and $C$ be the sets such that $A \cup B=A \cup C$ and $A \cap B=A \cap C$. Show that $B = C$
The set $A = \{ x:x \in R,\,{x^2} = 16$ and $2x = 6\} $ equals
Given the sets $A=\{1,3,5\}, B=\{2,4,6\}$ and $C=\{0,2,4,6,8\},$ which of the following may be considered as universal set $(s)$ for all the three sets $A$, $B$ and $C$
$\{0,1,2,3,4,5,6,7,8,9,10\}$
In the following state whether $\mathrm{A = B}$ or not :
$A = \{ x:x$ is a multiple of $10\} ;B = \{ 10,15,20,25,30 \ldots \ldots \} $
Write the set $A = \{ 1,4,9,16,25, \ldots .\} $ in set-builder form.