14.Semiconductor Electronics
medium

In the given circuit the current through Zener Diode is close to.......$mA$

A

$0$

B

$6.7$

C

$4$

D

$6$

(JEE MAIN-2019)

Solution

$12-500\left(2 i_{1}+i_{2}\right)-10=0$

$\Rightarrow \quad 2 i_{1}+i_{2}=\frac{2}{500}=\frac{1}{250}$

$< i_1$ when zenor has break down. $\mathrm{So}, \mathrm{i}_{2}=0$

Standard 12
Physics

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