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14.Semiconductor Electronics
medium
In the given circuit the current through Zener Diode is close to.......$mA$

A
$0$
B
$6.7$
C
$4$
D
$6$
(JEE MAIN-2019)
Solution

$12-500\left(2 i_{1}+i_{2}\right)-10=0$
$\Rightarrow \quad 2 i_{1}+i_{2}=\frac{2}{500}=\frac{1}{250}$
$< i_1$ when zenor has break down. $\mathrm{So}, \mathrm{i}_{2}=0$
Standard 12
Physics